Question

si tg=12/5 y 180≤α≤270
sen α? cos α?

Answer 1

Respuesta:

co = cateto opuesto

ca = cateto adyacente

h = hipotenusa

$\tan( \alpha ) = \frac{12}{5} = \frac{co}{ca} \\ {h}^{2} = {co}^{2} + {ca}^{2} \\ {h}^{2} = {12}^{2} + {5}^{2} \\ {h}^{2} = 144 + 25 \\ {h}^{2} = 169 \\ h = 13 \\ \sin( \alpha ) = \frac{co}{h} = \frac{12}{13} \\ \cos( \alpha ) = \frac{ca}{h} = \frac{5}{13}$