Question

Si $2^{n}=3$ entonces determine el valor de E
$E=\frac{2^{n+1}+2^{\frac{1}{n}}-4^n}{2^{n+2}-9}$

Answer 1

Respuesta:

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Explicación paso a paso:

$E= \frac{ (2^{n}*2)+\sqrt[n]{2} -(2^n )^{2}} {((2^{2})2^{n})-3^{2} } \\E= \frac{ (3^{})(2)+\sqrt[n]{2} -(3 )^{2}} {(2^{2} )(3)-3^{2} } \\\\E=\frac{6-9+\sqrt[n]{2}}{12-9} \\E=\frac{\sqrt[n]{2}-3}{3}$