Question

si sen β= 1/2 , establece las cinco razones trigonométricas restantes.

Answer 1

Vemos.

cosβ = √(1 - sen²β) = √(1 - 1/4) = √3/2

tgβ = senβ/cosβ = 1/2 / (√3/2) = 1/√3 = √3/3

cotgβ = 1/tgβ = √3

secβ = 1/cosβ = 2/√3 = 2 √3/3

cosecβ = 1/senβ = 2

Mateo.