Si se tienen 216g de plata cuantas moles de óxido de plata se podrian producir (Ag:108g/mol;O:16g/mol)
A:1
B:2
C:3
D:4
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n = masa / Mm
Mm Ag2O=
Ag = 2 x 108 = 216 g/mol
O =1 x 16 = 16 g/mol
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Mm = 232 g/mol
n = 216 g / 232 g/mol
n= 0.931 mol de plata
Mm Ag2O=
Ag = 2 x 108 = 216 g/mol
O =1 x 16 = 16 g/mol
``````````````````````````````````````
Mm = 232 g/mol
n = 216 g / 232 g/mol
n= 0.931 mol de plata
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