Question

si se deja caer libremente un objeto en la luna y en Júpiter Determine la velocidad que alcanzará y la distancia que caerá al cabo de 5 seg . gL=gt/6 gj=80.T​

Answer 1

 Las velocidades y las distancias alcanzadas por un objeto son :

  Vfl  8.165m/s       Vfj = 3920m/s     hL = 20.41m     hJ = 9800m

  Para calcular los valores de velocidad y distancia alcanzada por un objeto que se deja caer en la Luna y en Júpiter se debe aplicar las ecuaciones de caída libre como se muestra a continuación :

     

  Vo = O

  Vfl = ?    velocidad final de la luna

  Vfj = ?    velocidad final de júpiter

  hL = ?      altura de la luna

  hJ = ?      altura de júpiter

  t = 5s

  gL = gt/6   = 9.8m/s²/6   =  1.633m/s²

  gj = 80*gt  = 80*90m/s² =  784m/s²

  aplicando las ecuaciones de caída libre tenemos :

   Vfl = gL*t    ⇒   Vfl = 1.633m/s²*5s   ⇒   Vfl  8.165m/s

   Vfj = gj*t     ⇒   Vfj = 784m/s²*5s     ⇒   Vfj = 3920m/s

  hallando las distancias tenemos :

  hL = g*t²/2    ⇒  hL = 1.633m/s²*( 5s)²/2   ⇒ hL = 20.41m

  hJ = g*t²/2    ⇒  hJ = 784m/s²*(5s)²/2       ⇒  hJ = 9800m

Answer 2

Respuesta:

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