si se cuenta con 980g. de fecl3 para realizar la sgte operacion quimica:fecl3 + NaOH ----------fe(oh)3 + Nacl¿Cuantos gramos de fe(oh)3 se produciran?
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FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
Mm FeCl3 = 162.20 g/mol
Fe(OH)3 = 106.86 g/mol
g Fe(OH)3 = 980 g FeCl3 x 1 mol FeCl3 x 1 mol Fe(OH)3 x 106.86 gFe(OH)3
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162.20 g FeCl3 1 mol FeCl3 1 mol Fe(OH)3
g Fe(OH)3 = 645.64
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