Question

Si: P(x) = x² + x+ 5 Q(x) = 5x² + 2x - 3 R(x) = -3x³ - 4x + 1 calcular: P(x) + Q(x) + R(x)​ ayuda es para hoy doy corona​

Answer 1

Respuesta:

${x}^{2} + x + 5 + 5 {x}^{2} + 2x - 3 + ( - 3 {x}^{3} - 4x + 1 = \\ 6 {x}^{2} + 3x + 2 - 3 {x}^{3} - 4x + 1 = \\ 6 {x}^{2} - x + 3 - 3 {x}^{3} = \\ - 3 {x}^{3} + 6 {x}^{2} - x + 3$