Question

Si log3p = 5 y log3q =-2 calcula:
A) log3 (p×q)
B)log3 p2
C)log3 (p5/q)
Alguien me ayuda xfa..!!

Answer 1

Log3p = 5
Log3q = -2

A) Log3(pq) = Log3p + Log3q = 5 - 2 = 3

B) Log3p² = 2 Log3p = 2(5) = 10

C) Log3(p^5/q) = Log3p^5 - Log3q = 5 Log3p - Log3q = 5(5) + 2 = 25+2 = 27