Question

Si f(x)= x^2-4x+9, obtén el valor de f-(1/2), f(3)

Answer 1

Respuesta:

1,28843o286

Explicación paso a paso:

Answer 2

Si $f(x)= x^{2} - 4x + 9$, obtén el valor de f: $-\frac{1}{2}$  ,   f: $3$

$f: -(\frac{1}{2})$

$f(x)= x^2-4x+9$

$f(-\frac{1}{2} )= -\frac{1}{2} ^2-4(-\frac{1}{2} )+9$

$f(-\frac{1}{2} )= \frac{1}{4} -4(-\frac{1}{2})+9$

$f(-\frac{1}{2})= \frac{1}{4} +\frac{4}{2} +9$

$f(-\frac{1}{2} )= \frac{1}{4} +2+9$

$f(-\frac{1}{2} )= \frac{9}{4} +9$

$f(-\frac{1}{2} )= \frac{45}{4}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

$f: 3$

$f(x)= x^2-4x+9$

$f(3)= 3^2-4(3)+9$

$f(3)= 9-12+9$

$f(3)= -3 +9$

$f(3)= 6$