Question

Si f(x)=senx+cos2x+tg4x. Hallar f (π/2)
Porfa es Urgente

Answer 1

Respuesta:

     0

Explicación paso a paso:

f(x)=senx+cos2x+tg4x  

 f (π/2) = sen (π/2) + cos [ 2 (π/2) ] + tg [ 4 (π/2) ]

 f (π/2) = sen (π/2)  + cos (2π/2)  +  tg (4π/2)

 f (π/2) = sen (π/2)  + cos (π ) + tg  (2π )

f (π/2) = 1  + ( -1 ) + 0 = 1 - 1 + 0

f (π/2) = 0