Question

si: f(x)= 3× -1/2, hallar f(1), f(1/2), f(0), f(2)
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Answer 1

Respuesta:

$f(x)=3x-\dfrac{1}{2}$

$f(1)=3(1)-\dfrac{1}{2}\\\\f(1)=3-\dfrac{1}{2}\\\\f(1)=\dfrac{6}{2} -\dfrac{1}{2}\\\\f(1)=\dfrac{6-1}{2}\\\\f(1)=\dfrac{5}{2}$

$f\left(\dfrac{1}{2} \right)=3\left(\dfrac{1}{2} \right) -\dfrac{1}{2}\\\\f\left(\dfrac{1}{2} \right)=\dfrac{3}{2}-\dfrac{1}{2}\\\\f\left(\dfrac{1}{2} \right)=\dfrac{3-1}{2}\\\\f\left(\dfrac{1}{2} \right)=\dfrac{2}{2}\\\\f\left(\dfrac{1}{2} \right)=1$

$f(0)=3(0)-\dfrac{1}{2}\\\\f(0)=-\dfrac{1}{2}$

$f(2)=3(2)-\dfrac{1}{2}\\\\f(1)=6-\dfrac{1}{2}\\\\f(1)=\dfrac{12}{2} -\dfrac{1}{2}\\\\f(1)=\dfrac{12-1}{2}\\\\f(1)=\dfrac{11}{2}$