Question

Si el sen θ = 1/5 , calcula N = ctg2θ + 1

Answer 1

Explicación paso a paso:

Sen θ = 1/5

5² = 1² + x²

25 = 1 + x²

√24 = x

2√6= x

N = ctg² θ + 1

N = (2√6)² + 1

N = 4 × 6 + 1

N = 24 + 1

N= 25