Question

si cos42=1/sec(x+15) hallar ctg^2(x+3) ayuda plis​

Answer 1

Respuesta:

= 3

Explicación paso a paso:

Desarrollemos:

cos42 = 1/sec(x+15)

cos42 = 1/[1/cos(x+15)]

cos42 = cos(x+15)

Entonces:

42 = x + 15

42 - 15 = x

27 = x

Reemplazando:

= ctg^2(x + 3)

= [ctg(27 + 3)]^2

= [ctg(30)]^2

= [√3]^2

= 3