Question

SI ALGUIEN ES EXPERTO EN ALGEBRA QUE ME AYUDE PORFAVOR NECESITO URGENTE PARA HOY

Answer 1

Respuesta:

Resultado=1

Explicación paso a paso:

$\frac{ \frac{{x}^{2} + 4x + 3}{ {x}^{2} + 5x + 6} - \frac{ {x}^{2} + 5x + 6}{ {x}^{2} + 6x + 8}}{ \frac{ {x}^{2} + 8x + 15}{ {x}^{2} + 7x + 12} - \frac{ {x}^{2} + 8x + 15}{ {x}^{2} + 7x + 10}} \\ \frac{ \frac{(x + 3)(x + 1)}{(x + 3)(x + 2)} - \frac{(x + 3)(x + 2)}{(x + 4)(x + 2)}}{ \frac{(x + 5)(x + 3)}{(x + 4)(x + 3)} - \frac{(x + 5)(x + 3)}{(x + 5)(x + 2)}} \\ \frac{ \frac{(x + 1)}{(x + 2)} - \frac{(x + 3)}{(x + 4)}}{ \frac{(x + 5)}{(x + 4)} - \frac{(x + 3)}{(x + 2)}} \\ \frac{ \frac{(x + 1)(x + 4) - (x + 3)(x + 2)}{(x + 2)(x + 4)} }{ \frac{(x + 5)(x + 2) - (x + 3)(x + 4)}{(x + 2)(x + 4)} } \\ \frac{ \frac{ {x}^{2} + 5x + 4 - {x}^{2} - 5x - 6 }{(x + 2)(x + 4)} }{ \frac{ {x}^{2} + 7x + 10 - {x}^{2} - 7x - 12}{(x + 2)(x + 4)} } \\ \frac{ \frac{ - 2}{(x + 2)(x + 4)} }{ \frac{ - 2}{(x + 2)(x + 4)} } \\ \frac{ - 2}{(x + 2)(x + 4)} \times \frac{(x + 2)(x + 4)}{ - 2} \\ 1$