Question

Si abcd(4)= 1202(5), halla a + b + c + d

a) 3 c) 5
b) 4 d) 6

Answer 1

Explicación paso a paso:

a(4)³ + b(4²) + 4c + d = 5³ + 2(5)² + 2

64a + 16b + 4c + d = 125 + 50 + 2

64a + 16b + 4c + d = 177

a = 2

128 + 16b + 4c + d = 177

16b + 4c + d = 49

b = 3

48 + 4c + d = 49

4c + d = 1

c = 0

d = 1

Piden :

a + b + c + d = 2 + 3 + 0 + 1 = 6