Si A%B = 5A + 2B
Hallar: M= (2%1) % (3%2)
Respuestas a la pregunta
Contestado por
9
por la regla de Operadores:
(2%1) = 5(2) + 2(1)
= 10 + 2
= 12
(3%2) = 5(3) + 2(2)
= 15 + 4
= 19
M = 12%19
M = 5(12) + 2(19)
M = 60 + 38
M = 98 Rtaaaaaaaaaaaaaaaaaaaaaaaa
(2%1) = 5(2) + 2(1)
= 10 + 2
= 12
(3%2) = 5(3) + 2(2)
= 15 + 4
= 19
M = 12%19
M = 5(12) + 2(19)
M = 60 + 38
M = 98 Rtaaaaaaaaaaaaaaaaaaaaaaaa
Contestado por
4
A% B = 5A+2B
HALLAR
M = (2%1)%(3%2)
2%1 = 5*2+2*1 3%2 = 5*3+2*2
= 10+2 = 15+4
2%1 = 12 3%2 = 19
HALLANDO
(2%1)% (3%2)
12% 19 = 12*5+2*19
= 60+38
(2%1)%(3%2) = 98
HALLAR
M = (2%1)%(3%2)
2%1 = 5*2+2*1 3%2 = 5*3+2*2
= 10+2 = 15+4
2%1 = 12 3%2 = 19
HALLANDO
(2%1)% (3%2)
12% 19 = 12*5+2*19
= 60+38
(2%1)%(3%2) = 98
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