Question

Separar en terminos y luego resolver

A) 3^√1-37/64 - (-1/2+5/6)^2 + (-3/8=
B) -19/2 + 30/4.(-1/3) + (-1/2)^2 - 3^√-1/8=

Answer 1

Explicación paso a paso:

A)

$\sqrt[3]{1 - \frac{37}{64} } - ( - \frac{1}{2 } + \frac{5}{6} )^{2} + ( - \frac{3}{8} ) \\ \\ \sqrt[3]{ \frac{64 - 37}{64} } - ( \frac{ - 3 + 5}{6} ) ^{2} - \frac{3}{8} \\ \\ \sqrt[3]{ \frac{27}{64} } - ( \frac{2}{6} ) ^{2} - \frac{3}{8} \\ \\ \frac{3}{4} - ( \frac{1}{3} )^{2} - \frac{3}{8} \\ \\ \frac{3}{4} - \frac{1}{9} - \frac{3}{8} = \frac{54 - 8 - 27}{72} = \frac{19}{72}$

B)

$- \frac{19}{2} + \frac{30}{4} \times ( - \frac{1}{3} ) + {( \frac{1}{2}) }^{2} - \sqrt[3]{ - \frac{1}{8} } \\ \\ - \frac{19}{2} - \frac{30}{12} + \frac{1}{4} - ( - \frac{1}{2} ) \\ \\ - \frac{19}{2} - \frac{5}{2} + \frac{1}{4} + \frac{1}{2} = \\ \\ \frac{ - 38 - 10 + 1 + 2}{4} = - \frac{45}{4}$