Question

sean a y b dos magnitudes tales que a es dp a b^2. hallar a cuanto: b=3, si:A=8, cuando:b=2

Answer 1

$\frac{a}{ {b}^{2} } = \frac{8}{ {3}^{2} } = \frac{a}{ {2}^{2} } \\ = \frac{8}{9} = \frac{a}{4} \\ a = \frac{8 \times 4}{9} = \frac{32}{9}$

$a = \frac{32}{9} = 3.555...$