Question

se tiene: log₂(x+y)=1/4 ; log₂(x²-y²)=1/3 ; calcular log₂(x-y)

Answer 1

Respuesta:

1/12

Explicación paso a paso:

log₂(x²-y²)=1/3

log₂[(x+y)(x-y)] =1/3

log₂(x+y) + log₂(x-y) =1/3

1/4    +  log₂(x-y) =1/3

log₂(x-y) =1/3 - 1/4

log₂(x-y) =1/12