Se disuelven 30,0 g de Cloruro de Sodio en 90,0 g de agua a 25oC. Calcular la fracción molar de NaCl en la solución.
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Mm NaCl = 58.45 g/mol
H2O = 18 g/mol
n = mol/Mm
nsto = 30 g / 58.45 g/mol = 0.513 mol de sal
nsolvente = 90 g/ 18 g/mol = 5 mol
ntotal = sto + n svte
n total = (0.513 mol + 5 mol ) = 5.513 mol
Xsto = n sto
````````````````````
n total
Xsto = 0.513 mol
````````````````
5.513 mol
Xsto = 0.09 (sal)
Xsvte = n svte
````````````````````
n total
Xsvte = 5 mol
````````````````
5.513 mol
Xsvte = 0.90 (agua)
H2O = 18 g/mol
n = mol/Mm
nsto = 30 g / 58.45 g/mol = 0.513 mol de sal
nsolvente = 90 g/ 18 g/mol = 5 mol
ntotal = sto + n svte
n total = (0.513 mol + 5 mol ) = 5.513 mol
Xsto = n sto
````````````````````
n total
Xsto = 0.513 mol
````````````````
5.513 mol
Xsto = 0.09 (sal)
Xsvte = n svte
````````````````````
n total
Xsvte = 5 mol
````````````````
5.513 mol
Xsvte = 0.90 (agua)
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