Se almacena dioxido de carbono en cilindros de 0,5 pies cubicos con un peso de una libra. Si los cilindros pueden someterse a una temperatura de 120 grados F. Cual sera su presion (usando ley de los gases y la ecuacion de estado)
Respuestas a la pregunta
Contestado por
0
datos:
V = 0.5 pie³ convertir a litro
L = 50 x 28.31 = 1415,5 Litros
m = 1 libra
1 libra = 453.59 g
T = 120 ºF
convertir ºF a ºC
ºC = ºF - 32/1.8
ºC = 120 - 32 / 1.8
ºC = 48.89
Convertir ºC a K
K = ºC + 273
K = 48.89 + 273 = 321.89 K
2. calcular moles
Mm CO2 = 44 g/mol
n = masa/Mm
n = 453.59 g/ 44 g/mol
n = 10.308 moles
3. aplicar la Ley de las Gases Ideales: V · P = n · R · T
R = 0.0821 (L atm/mol K)
P = 10.308 mol x 0.0821 (L atm / mol K) x 321.89 K
````````````````````````````````````````````````````````````````````
1415,5 Litros
P = 0.19 atm
V = 0.5 pie³ convertir a litro
L = 50 x 28.31 = 1415,5 Litros
m = 1 libra
1 libra = 453.59 g
T = 120 ºF
convertir ºF a ºC
ºC = ºF - 32/1.8
ºC = 120 - 32 / 1.8
ºC = 48.89
Convertir ºC a K
K = ºC + 273
K = 48.89 + 273 = 321.89 K
2. calcular moles
Mm CO2 = 44 g/mol
n = masa/Mm
n = 453.59 g/ 44 g/mol
n = 10.308 moles
3. aplicar la Ley de las Gases Ideales: V · P = n · R · T
R = 0.0821 (L atm/mol K)
P = 10.308 mol x 0.0821 (L atm / mol K) x 321.89 K
````````````````````````````````````````````````````````````````````
1415,5 Litros
P = 0.19 atm
Otras preguntas