sabiendo que 15L de hidrogeno se encuentran a 27°c y sometidos a una presion de 3atm .determine la masa del gas (P.Mh2=2g/mol)
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v = 15 L
P = 3 atm.
T = 27 + 273 = 300 K
R = 0.0821 (atm. L / mol K)
V x P = n x R x T
n = V x P
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R x T
n = 15 L x 3 atm
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0.0821(atm.L/mol K) x 300 K
n = 1.827 mol
n = masa / Mm
masa = n x Mm
masa = 1.827 mol x 2 g/mol
m = 3.654 g
P = 3 atm.
T = 27 + 273 = 300 K
R = 0.0821 (atm. L / mol K)
V x P = n x R x T
n = V x P
````````````
R x T
n = 15 L x 3 atm
````````````````````````````
0.0821(atm.L/mol K) x 300 K
n = 1.827 mol
n = masa / Mm
masa = n x Mm
masa = 1.827 mol x 2 g/mol
m = 3.654 g
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