Question

RETO 2: Resuelve ecuaciones e inecuaciones
1. (5 – 3x) – (– 4x + 6) = (8x + 11) – (3x – 6)

2. (x – 2)∧2 – (3 – x )∧2 = 1

3. (m – 1)∧2 – (2 – m )∧2 > 7

4. 3(x + 2) + 2(3x – 1) – (x – 1) ≤ 5 + 2(5x + 2) – 2(2x + 3)

Answer 1

$\bold{Hola!}$

$\underline{\mathbb{TEMA: ECUACIONES}}$

1. (5 – 3x) – (– 4x + 6) = (8x + 11) – (3x – 6)

5-3X+4X-6=8X+11-3X+6

5+4X-6=8X+11+6

-1+4X=8X+17

4X+8X=17+1

-4X=18

$\boxed{X=-9/2}$

2.$(x -2)^{2} -(3-x)^{2} =1$

$x^{2} -4x+4-(9-6x+x^{2} )=1$

$x^{2} -4x+4-9+6x-x^{2} =1$

$2x-5=1$

$2x=6$

$\boxed{x=3}$

3)(m – 1)∧2 – (2 – m )∧2 > 7

m2-2m+1-(4-4m+m2) >7

m2-2m+1-4-4m+m2 >7

2m-3>7

2m>10

$\boxed{m >5}$

4. 3(x + 2) + 2(3x – 1) – (x – 1) ≤ 5 + 2(5x + 2) – 2(2x + 3)

3x+6+6x -2-x+1≤5+10x+4-4x-6

8x+5≤3+6x

8x-6x≤3-5

2x≤-2

$\boxed{x \leq -1}$

Espero que te sirva Saludos!!