Question

resuelve
x^{2} + 6x - 8 : 0 con formula general

Answer 1

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${x}^{2} + 6x - 8 = 0 \\ x = \frac{ - 6 \frac{ + }{} \sqrt{ {6}^{2} - 4(1)( - 8) } }{2(1)} \\ x= \frac{ - 6 \frac{ + }{} \sqrt{36 + 32} }{2} \\ x= \frac{ - 6 \frac{ + }{} \sqrt{68} }{2} \\ x = \frac{ - 6 \frac{ + }{} 2 \sqrt{17} }{2} \\ x = - 3 + \sqrt{17} \: \: \: o \: \: \: x = - 3 - \sqrt{17}$