Question

Resuelve tambien los siguientes problemas.
a)9x²-8x=0
b) 17x² + 2x=0
c) 7x² +5=7
d) 3x² + 6 =9​

me pueden ayudar porfa se los pido

Answer 1

Explicación paso a paso:

a)

${9x}^{2} - 8x = 0 \\ {9x}^{2} = + 8x \\ \frac{ {x}^{2} }{x} = \frac{8}{9}$

${x}^{2 - 1} = 0.888 \\ x = 0.888$

b)

$17 {x}^{2} + 2x = 0 \\ {17x}^{2} = - 2x \\ \frac{ {x}^{2} }{x} = - \frac{2}{17}$

$x = - 0.1176$

c)

${7x}^{2} + 5 = 7 \\ {7x}^{2} = 7 - 5 \\ {7x}^{2} = 2$

${x}^{2} = \frac{2}{7} \\ x = \sqrt{0.2857} \\ x = 0.5345$

d)

${3x}^{2} + 6 = 9 \\ {3x}^{2} = 9 - 6 \\ {3x}^{2} = 3$

${x}^{2} = \frac{3}{3} \\ x = \sqrt{1 } \\ x = 1$