Matemáticas, pregunta formulada por darwintamaydj1983, hace 1 año

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Contestado por sonia2302
1

Explicación paso a paso:

(2 +  \frac{3}{4} )(1 -  \frac{5}{11})(2 -  \frac{3}{4}  )(1 +  \frac{2}{5} ) \times  \frac{5}{7}  \times 1 \frac{3}{5}  =  \\  \\ ( \frac{8 + 3}{4} )( \frac{11 - 5}{11} )( \frac{8 - 3}{4} )( \frac{5 + 2}{5} ) \times  \frac{5}{7}  \times  \frac{5 \times 1 + 3}{5}  =  \\  \\  \frac{11}{4}  \times  \frac{6}{11}  \times  \frac{5}{4}  \times  \frac{7}{5}  \times  \frac{5}{7}  \times  \frac{8}{5}  =  \frac{92.400}{30.800}  \\  \\  simplificamos \:  \frac{92.400}{30.800} = 3

(1 +  \frac{1}{2}  -  \frac{3}{4} )(1 -  \frac{1}{2}  +  \frac{3}{4} )( \frac{3}{4}  -  \frac{1}{2} )( \frac{4}{5}  - 2) \times 3 \frac{5}{9}  =  \\  \\ ( \frac{4 + 2 - 3}{4} )( \frac{4 - 2 + 3}{4} )( \frac{3 - 2}{4} )( \frac{4 - 10}{2} ) \times  \frac{9 \times 3 + 5}{9}  =  \\  \\  \frac{3}{4}  \times  \frac{5}{4}  \times  \frac{1}{4}  \times ( -  \frac{6}{2} ) \times  \frac{32}{9}  =  -  \frac{2880}{1152}  \\  \\ simplificamos \: y \: queda \:  -  \frac{5}{2}

(3 +  \frac{2}{5} )(1 -  \frac{12}{17} )( \frac{3}{2}  +  \frac{5}{4} )( \frac{15}{11}  - 1) \\  \\ ( \frac{15 + 2}{5} )( \frac{17 - 12}{17} )( \frac{6 + 5}{4} )( \frac{15 - 11}{11} ) =   \\  \\ \frac{17}{5}  \times  \frac{5}{17}  \times  \frac{11}{4}  \times  \frac{4}{11}  =  \frac{3740}{3740}  = 1

(2 +  \frac{1}{5} ) -  \frac{3}{4} ( \frac{1}{5}  +  \frac{1}{15} ) +  \frac{4}{100} (4 +  \frac{3}{8} ) =  \\  \\  (\frac{10 + 1}{5} ) -  \frac{3}{4} ( \frac{3 + 1}{15} ) +  \frac{1}{25} ( \frac{32 + 3}{8} ) =  \\  \\  \frac{11}{5}   -  \frac{3}{4}  \times   \frac{4}{15} +  \frac{1}{25}  \times  \frac{35}{8}  =  \\  \\  \frac{11}{5}  -  \frac{12}{60}  +  \frac{35}{200}  =  \\  \\  \frac{11}{5}  -  \frac{1}{5}  +  \frac{7}{40}  =  \frac{88 - 8 + 7}{40}  =  \frac{87}{40}

(3 \frac{5}{11} ) \div (1 -  \frac{3}{22} ) =  \\  \\  (\frac{11 \times 3 + 5}{11} ) \div ( \frac{22 - 3}{22} ) =  \\  \\  \frac{38}{11}  \div  \frac{19}{22}  =  \frac{836}{209}  =  \frac{76}{19}

7(4  + \frac{1}{5} ) \div ( \frac{9}{10}  + 4) =  \\  \\ 7( \frac{20 + 1}{5} ) \div ( \frac{9 + 40}{4} ) =  \\  \\ 7 \times  \frac{21}{5}  \div  \frac{49}{4}  =  \\  \\  \frac{147}{5}  \div  \frac{49}{4}  =  \frac{588}{245}  =  \frac{12}{5}

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