Question

resuelve las siguientes sumas y restas de fracciones heterogéneas​
doy corona ayudaaaa

Answer 1

Respuesta:

$\frac{3}{5} + \frac{6}{4} = \frac{21}{10} \\ \\ \frac{1}{8} + \frac{4}{6} = \frac{19}{24} \\ \\ \frac{6}{10} + \frac{9}{5} = \frac{12}{5} \\ \\ \frac{2}{5 } + \frac{1}{3} = \frac{11}{15} \\ \\ \frac{8}{2} + \frac{4}{8} = \frac{9}{2} \\ \\ \frac{2}{7} + \frac{9}{3} = \frac{23}{7} \\ \\ \frac{2}{11} + \frac{10}{9} = \frac{128}{99} \\ \\ \frac{10}{12} + \frac{3}{6} = \frac{4}{3} \\ \\ \frac{12}{9} - \frac{2}{3} = \frac{2}{3} \\ \\ \frac{3}{7} + \frac{2}{3} = \frac{23}{21} \\ \\ \frac{10}{16} + \frac{9}{4} = \frac{23}{8} \\ \\ \frac{23}{4} - \frac{5}{2} = \frac{13}{4}$