Question

Resuelve las siguientes operaciones de potencias

Answer 1

$a)9 \times {( - 3)}^{3} \times ( - 3) = {( - 3)}^{2} \times {( - 3)}^{3} \times ( - 3) = {( - 3)}^{2 + 3 + 1} = {( - 3) }^{6} = 729$

$b) {( - 5)}^{2} \times 125 = {( - 5)}^{2} \times {5}^{3} = {5}^{2} \times {5}^{3} = {5}^{2 + 3} = {5}^{5} = 3125$

$c) {(2 + 3)}^{3} \times {5}^{2} = {5}^{3} \times {5}^{2} = {5}^{3 + 2} = {5}^{5} = 3125$

$d)64 \times {2}^{3} \times 4 = {2}^{6} \times {2}^{3} \times {2}^{2} = {2}^{6 + 3 + 2} = {2}^{11} = 2048$

$e) {(5 - 7)}^{2} \times {( - 2)}^{3} = {( - 2)}^{2} \times {( - 2)}^{3} = {( - 2)}^{2 - 3} = {( - 2)}^{ - 1} = \frac{1}{ {( - 2)}^{1} } = - \frac{1}{2}$

$f)27 \times 9 = {3}^{3} \times {3}^{2} = {3}^{3 + 2} = {3}^{5} = 243$

$g)(9 + 2) \times {( - 11)}^{2} = 11 \times {( - 11)}^{2} = 11 \times {11}^{2} = {11}^{1 + 2} = {11}^{3} = 1331$

$h)16 \times 4 \times 2 = {2}^{4} \times {2}^{2} \times 2 = {2}^{4 + 2 + 1} = {2}^{7} = 128$