Question

Resuelve las siguientes operaciones de números racionales...

Answer 1

a) $\frac{\frac{-4}{6}+\frac{7}{8}}{\frac{-5}{8}-\frac{11}{20}}$

$\frac{\frac{-4}{6}+\frac{7}{8}}{\frac{-5}{8}-\frac{11}{20}}$

$=\frac{-\frac{4}{6}+\frac{7}{8}}{-\frac{5}{8}-\frac{11}{20}}$

$Hay\:que\:simplificar\: -\frac{5}{8} -\frac{11}{20} \:en\:una\:fraccion\: -\frac{47}{40}$

$=\frac{-\frac{4}{6}+\frac{7}{8}}{-\frac{47}{40}}$

$Cancelar\:\frac{4}{6} :\:\frac{2}{3}$

$=\frac{-\frac{2}{3}+\frac{7}{8}}{-\frac{47}{40}}$

$\frac{-\frac{2}{3}+\frac{7}{8}}{\frac{47}{40}}=\frac{\left(-\frac{2}{3}+\frac{7}{8}\right)\cdot \:40}{47}$

$=-\frac{\left(-\frac{2}{3}+\frac{7}{8}\right)\cdot \:40}{47}$

$=-\frac{40\cdot \frac{5}{24}}{47}$

$=-\frac{\frac{25}{3}}{47}$

$=-\frac{25}{141}$

b) $\frac{\frac{9}{15}-\frac{-7}{12}}{\frac{-6}{2}+\frac{-8}{3}}$

$=\frac{\frac{9}{15}+\frac{7}{12}}{\frac{-6}{2}+\frac{-8}{3}}$

$=\frac{\frac{9}{15}+\frac{7}{12}}{-\frac{6}{2}-\frac{8}{3}}$

$=\frac{\frac{9}{15}+\frac{7}{12}}{-3-\frac{8}{3}}$

$=\frac{\frac{3}{5}+\frac{7}{12}}{-3-\frac{8}{3}}$

$=\frac{\frac{3}{5}+\frac{7}{12}}{-\frac{17}{3}}$

$=\frac{\frac{71}{60}}{-\frac{17}{3}}$

$=-\frac{\frac{71}{60}}{\frac{17}{3}}$

$=-\frac{71\cdot \:3}{60\cdot \:17}$

$=-\frac{71\cdot \:3}{1020}$

$=-\frac{213}{1020}$

$=-\frac{71}{340}$

c) $\frac{\frac{-4}{10}\cdot \frac{-3}{2}}{\frac{6}{8}\cdot \frac{4}{5}}$

$=\frac{\frac{3}{2}\cdot \frac{4}{10}}{\frac{6}{8}\cdot \frac{4}{5}}$

$=\frac{\frac{3}{2}\cdot \frac{4}{10}}{\frac{3}{5}}$

$=\frac{\frac{3}{5}}{\frac{3}{5}}$

$=1$

d) $\frac{\frac{15}{6}\div \frac{-7}{2}}{\frac{-2}{5}\div \frac{6}{7}}$

$\frac{15}{6}$÷$\frac{-7}{2} :\:-\frac{7}{2}$

$-\frac{2}{5}$÷$\frac{6}{7} :\:-\frac{7}{15}$

$=\frac{-\frac{7}{2}}{-\frac{7}{15}}$

$Simplificamos\: =\frac{-\frac{7}{2}}{-\frac{7}{15}}\:y\:eso\:nos\:da\::7\frac{1}{2}$

$=7\frac{1}{2}$

$Buena\:suerte\:con\:tus\:tareas\::ProfeAndresFelipe :)$