Question

resuelve las siguientes ecuaciones:y a partir
de la numero 4 has la prueba

1. 3{[(x-2)+4x]-(x-3)}= 4-(x-12)

2. -{4(d+3)-5[3d-2(2d+7)]-8]= -10d-6

3. -3(6-4x)= 4-{5x-[6x-(4x-(3x+2))]}


con prueba:

4. n-5= 3n+25

5. 6t-4= 3t+2

6. 10+2b= 7b-15

7. 7x-2= 11x+5

8. 5y+y+6= 8y+4

Answer 1

 n-5= 3n+25
n-3n=25+5
-2n=30
n=30/-2
n= -15

 n-5= 3n+25
-15-5=3(-15)+25
-20= -45+25
-20= -20
................................................
 6t-4= 3t+2
6t-3t=2+4
3t=6
t=6/3
t=2

 6t-4= 3t+2
6(2)-4=3(2)+2
12-4=6+2
8=8
....................................
10+2b= 7b-15
2b-7b= -15-10
-5b= -25
b= -25/-5
b=5


10+2b= 7b-15
10+2(5)=7(5)-15
10+10=35-15
20=20
......................................................
 7x-2= 11x+5
7x-11x=5+2
-4x=7
x= - 7/4

 7x-2= 11x+5
7(-7/4)-2=11(-7/4)+5
-49/4-2= -77/4+5
-49-8  = -77+20 
   4           4
-57  = -57 
 4        4
......................................
5y+y+6= 8y+4
6y+6=8y+4
6y-8y=4-6
-2y= -2
y= -2/-2
y=1

5y+y+6= 8y+4
5(1)+1+6=8(1)+4
5+7=8+4
112=12
...........................
 3{[(x-2)+4x]-(x-3)}= 4-(x-12)
 3{[x+4x-2]-x+3}= 4-x+12
 3{[5x-2]-x+3}= 4+12-x
 3{5x-x+3-2}= 16-x
 3{4x+1}= 16-x
12x+3=16-x
12x+x=16-3
13x=13
x=13/13
x=1
..............................................................

 -{4(d+3)-5[3d-2(2d+7)]-8]= -10d-6
 -{4d+12-5[3d-4d-14]-8]= -10d-6
 -{4d+12-5[-d-14]-8]= -10d-6
 -{4d+12+5d+70-8]= -10d-6
 -{4d+5d+70+12-8]= -10d-6
 -{9d+74]= -10d-6
-9d-74= -10d-6
-9d+10d= -6+74
d=68
...............................
 -3(6-4x)= 4-{5x-[6x-(4x-(3x+2))]
 -18+12x= 4-{5x-[6x-(4x-3x-2)]
 -18+12x= 4-{5x-[6x-(x-2)]
 -18+12x= 4-{5x-[6x-x+2)]
 -18+12x= 4-{5x-[5x+2)]
 -18+12x= 4-{5x-5x-2]
-18+12x=4-(-2)
-18+12x=4+2
-18+12x=6
12x=6+18
12x=24
x=24/12
x=2