Resuelve las siguientes ecuaciones para encontrar el valor de la incognita
a) -18=9(d+1)
b) 6(b+5)=8
c)9t-8=5t+4
d)8m+27=2m-3
e) -3t-15=-9
f) 11-6k=-13
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a) -18=9(d+1)
-18 = 9d + 9
9d= -18 -9
d= -27/9
d= -3
b) 6(b+5)=8
6b + 30 = 8
6b= 8-30
b= -22/6
b= -11/3
c)9t-8=5t+4
9t-5t=4+8
4t=12
t=12/4
t= 3
d)8m+27=2m-3
8m-2m= -3-27
6m= -30
m= -30/6
m= -5
e) -3t-15=-9
-3t= -9+15
t= 6/-3
t= -2
f) 11-6k=-13
-6k= -13 -11
k= -24/-6
k= 4
-18 = 9d + 9
9d= -18 -9
d= -27/9
d= -3
b) 6(b+5)=8
6b + 30 = 8
6b= 8-30
b= -22/6
b= -11/3
c)9t-8=5t+4
9t-5t=4+8
4t=12
t=12/4
t= 3
d)8m+27=2m-3
8m-2m= -3-27
6m= -30
m= -30/6
m= -5
e) -3t-15=-9
-3t= -9+15
t= 6/-3
t= -2
f) 11-6k=-13
-6k= -13 -11
k= -24/-6
k= 4
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a)
-18 = 9 (d+1)
-18/9 = d+1
-2-1 = d
d = -3
b)
6(b+5) = 8
b+5 = 8/6
b = (4/3)-5
b = -11/3
c)
9t-8 = 5t + 4
9t-5t = 4+8
4t = 12
t = 12/4
t =3
d)
8m+27 = 2m-3
8m-2m = -3 -27
6m = -30
m = -30/6
m = -5
e)
-3t-15 = -9
3t = 9-15
3t = -6
t = -6/3
t = -2
f)
11-6k = -13
6k = 11+13
6k = 24
k = 24/6
k = 4
-18 = 9 (d+1)
-18/9 = d+1
-2-1 = d
d = -3
b)
6(b+5) = 8
b+5 = 8/6
b = (4/3)-5
b = -11/3
c)
9t-8 = 5t + 4
9t-5t = 4+8
4t = 12
t = 12/4
t =3
d)
8m+27 = 2m-3
8m-2m = -3 -27
6m = -30
m = -30/6
m = -5
e)
-3t-15 = -9
3t = 9-15
3t = -6
t = -6/3
t = -2
f)
11-6k = -13
6k = 11+13
6k = 24
k = 24/6
k = 4
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