Question

resuelve las siguientes ecuaciones lineales ​

Answer 1

Respuesta:

$a)2x + 10 = 16 \\ 2x = 16 - 10 \\ 2x = 6 \\ x = \frac{6}{2} \\ x = 3$

$b)10x - 8 = 8x \\ 10x - 8x = 8 \\ 2x = 8 \\ x = \frac{8}{2} \\ x = 4$

$c)2x + 3 = x - 9 \\ 2x - x = - 9 - 3 \\ x = - 12$

$d)7(3x + 2) - 5(4x - 3) = 4(x - 2) + 1 \\ 21x + 14 - 20x + 15 = 4x - 8 + 1 \\ x + 29 = 4x - 7 \\ 29 + 7 = 4x - x \\ 36 = 3x \\ \frac{36}{3} = x \\ 12 = x$

$e)x + 16 = 41 \\ x = 41 - 16 \\ x = 25$

$f)9x - 45 + 4x - 16 = 4 \\ 13x - 61 = 4 \\ 13x = 4 + 61 \\ 13x = 65 \\ x = \frac{65}{13} \\ x = 5$

$g)2x - 3 + x - 35 = 2 - 9x - 4 \\ 3x - 38 = - 2 - 9x \\ 3x + 9x = - 2 + 38 \\ 12x = 36 \\ x = \frac{36}{12} \\ x = 3$

$h)3(x - 2) + 9 = 0 \\ 3x - 6 + 9 = 0 \\ 3x + 3 = 0 \\ 3x = - 3 \\ x = \frac{ - 3}{3} \\ x = - 1$

$e)x + (x + 2) = 36 \\ x + x + 2 = 36 \\ 2x + 2 = 36 \\ 2x = 36 - 2 \\ 2x = 34 \\ x = \frac{34}{2} \\ x = 17$

$g)2(3x - 2) - (x + 3) = 8 \\ 6x - 4 - x - 3 = 8 \\ 5x - 7 = 8 \\ 5x = 8 + 7 \\ 5x = 15 \\ x = \frac{15}{5} \\ x = 3$