Question

resuelve las siguientes ecuaciones:
de la 12 a la 16
plis rápido esq. tengo que subirlo a la 1

Answer 1

Respuesta:

12)$14-\left(5x-1\right)\left(2x+3\right)=17-\left(10x+1\right)\left(x-6\right)$

    $-10x^2-13x+17=-10x^2+59x+23$

    $-10x^2-13x+17-17=-10x^2+59x+23-17$

    $-10x^2-13x=-10x^2+59x+6$

    $-10x^2-13x-\left(-10x^2+59x\right)=-10x^2+59x+6-\left(-10x^2+59x\right)$

    $-72x=6$

    $\frac{-72x}{-72}=\frac{6}{-72}$

    $x=-\frac{1}{12}$

13)$\left(x-2\right)^2+x\left(x-3\right)=3\left(x+4\right)\left(x-3\right)-\left(x+2\right)\left(x-1\right)+2$

     $2x^2-7x+4=2x^2+2x-32$

     $2x^2-7x+4-4=2x^2+2x-32-4$

     $2x^2-7x=2x^2+2x-36$

     $2x^2-7x-\left(2x^2+2x\right)=2x^2+2x-36-\left(2x^2+2x\right)$

     $-9x=-36$

     $\frac{-9x}{-9}=\frac{-36}{-9}$

     $x=4$

14)$\left(3x-1\right)^2-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)=0$

    $\left(3x-1\right)^2-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)$

    $=9x^2-6x+1-5\left(x-2\right)-\left(2x+3\right)^2-\left(5x+2\right)\left(x-1\right)$

    $=9x^2-6x+1-5\left(x-2\right)-\left(4x^2+12x+9\right)-\left(5x+2\right)\left(x-1\right)$

    $=9x^2-6x+1-5x+10-\left(4x^2+12x+9\right)-\left(5x+2\right)\left(x-1\right)$

    $=9x^2-6x+1-5x+10-4x^2-12x-9-\left(5x+2\right)\left(x-1\right)$

    $=9x^2-6x+1-5x+10-4x^2-12x-9-5x^2+3x+2$

    $=-20x+4$

    $-20x+4=0$

    $-20x=-4$

    $\frac{-20x}{-20}=\frac{-4}{-20}$

    $x=\frac{1}{5}$

15)$2\left(x-3\right)^2-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)=4x^2-12$

    $2\left(x-3\right)^2-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)$

    $=2\left(x^2-6x+9\right)-3\left(x+1\right)^2+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)$

    $=2\left(x^2-6x+9\right)-3\left(x^2+2x+1\right)+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)$

    $=2x^2-12x+18-3\left(x^2+2x+1\right)+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)$

    $=2x^2-12x+18-3x^2-6x-3+\left(x-5\right)\left(x-3\right)+4\left(x^2-5x+1\right)$

    $=2x^2-12x+18-3x^2-6x-3+x^2-8x+15+4\left(x^2-5x+1\right)$

    $=2x^2-12x+18-3x^2-6x-3+x^2-8x+15+4x^2-20x+4$

    $=4x^2-46x+34$

    $4x^2-46x+34=4x^2-12$

    $4x^2-46x+34-34=4x^2-12-34$

    $4x^2-46x=4x^2-46$

    $4x^2-46x-4x^2=4x^2-46-4x^2$

    $-46x=-46$

    $\frac{-46x}{-46}=\frac{-46}{-46}$

    $x=1$

16)$5\left(x-2\right)^2-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2=0$

    $5\left(x-2\right)^2-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2$

    $=5\left(x^2-4x+4\right)-5\left(x+3\right)^2+\left(2x-1\right)\left(5x+2\right)-10x^2$

    $=5\left(x^2-4x+4\right)-5\left(x^2+6x+9\right)+\left(2x-1\right)\left(5x+2\right)-10x^2$

    $=5x^2-20x+20-5\left(x^2+6x+9\right)+\left(2x-1\right)\left(5x+2\right)-10x^2$

    $=5x^2-20x+20-5x^2-30x-45+\left(2x-1\right)\left(5x+2\right)-10x^2$

    $=5x^2-20x+20-5x^2-30x-45+10x^2-x-2-10x^2$

    $=-51x-27$

    $-51x-27=0$

    $-51x=27$

    $\frac{-51x}{-51}=\frac{27}{-51}$

    $x=-\frac{9}{17}$