Question

Resuelve las siguientes ecuaciones cuadrática:
1.
$- 8x {}^{2} + 32$
2.
$- 10x {}^{2} + 160$


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Answer 1

Respuesta:

hole !

Resolviendo'

1)

$- 8 {x}^{2} + 32 = 0$

$- 8 {x}^{2} = 0 - 32$

$- 8 {x}^{2} = - 32$

${x}^{2} = \frac{ - 32}{ - 8}$

${x}^{2} = 4$

$\sqrt{ {x}^{2} } = \sqrt{4}$

$|x | = 2$

X1 = 2

X2 = -2

2)

$- {10x}^{2} + 160 = 0$

$- 10 {x}^{2} = 0 - 160$

$- {10x}^{2} = - 160$

${x}^{2} = \frac{ - 160}{ - 10}$

${x}^{2} = 16$

$\sqrt{ {x}^{2} } = \sqrt{16}$

$|x| = 4$

X1 = 4

X2 = -4

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Saludos