Question

resuelve las siguientes ecuaciones
AYUDA ​

Answer 1

Respuesta:

$a)2 - \frac{1}{5} (2x - 1) = \frac{7x}{10} \\ 2 - \frac{2x}{5} + \frac{1}{5} = \frac{7x}{10} \\ 10(2 - \frac{2x}{5} + \frac{1}{5} ) = 10 \times \frac{7x}{10} \\ 20 - 4x + 2 = 7x \\ 22 - 4x = 7x \\ 22 = 7x + 4x \\ 22 = 11x \\ 2 = x$

$b) \frac{x}{2} - \frac{x}{3} = \frac{1}{6} (x - \frac{3}{2} ) + x \\ \frac{x}{2} - \frac{x}{3} = \frac{x}{6} - \frac{1}{4} + x \\ 12( \frac{x}{2} - \frac{x}{3} ) = 12( \frac{x}{6} - \frac{1}{4} + x) \\ 6x - 4x = 2x - 3 + 12x \\ 2x = 14x - 3 \\ 3 = 14x - 2x \\ 3 = 12x \\ \frac{3}{12} = x \\ \frac{1}{4} = x$

$c) \frac{1}{2} ( \frac{x}{2} + 1) - \frac{2x}{3} = \frac{1}{6} (x - \frac{1}{2} ) \\ \frac{x}{4} + \frac{1}{2} - \frac{2x}{3} = \frac{x}{6} - \frac{1}{12} \\ 12( \frac{x}{4} + \frac{1}{2} - \frac{2x}{3} ) = 12( \frac{x}{6} - \frac{1}{12} ) \\ 3x + 6 - 8x = 2x - 1 \\ - 5x + 6 = 2x - 1 \\ 6 + 1 = 2x + 5x \\ 7 = 7x \\ 1 = x$

$d)11x - 5(2x + \frac{1}{2} ) = \frac{3}{5} (x - \frac{1}{2} ) - 1 \\ 11x - 10x - \frac{5}{2} = \frac{3x}{5} - \frac{3}{10} - 1 \\ 10(11x - 10x - \frac{5}{2} ) = 10( \frac{3x}{5} - \frac{3}{10} - 1) \\ 110x - 100x - 25 = 6x - 3 - 10 \\ 10x - 25 = 6x - 13 \\ 10x - 6x = - 13 + 25 \\ 4x = 12 \\ x = 3$