Question

resuelve las siguientes ecuaciones 4x elevado a la 2-3x=0 y x elevado a la 2-2x-3=0

Answer 1

A) 
$4x^{2} -3x+0=0 \\ \\ x_{1}| x_{2}= \frac{-(-3)+/- \sqrt{(-3)^{2}-4*4*0} }{2*4}= \frac{3+/- \sqrt{9} }{8} = \frac{3+/-3}{8}= \\ x_{1} = \frac{3+3}{8}= 0,75 \\ x_{2}= \frac{3-3}{8}=0$

B)
$x ^{2}-2x-3=0 \\ \\ x_1|x_2= \frac{-(-2)+/- \sqrt{(-2)^{2}-4*1*(-3)} }{2*1}= \frac{2+/- \sqrt{4+12} }2} = \frac{2+/- \sqrt{16} }{2}= \frac{2+/-4}{2} = \\  x_{1}= \frac{2+4}{2} =3 \\ x_2= \frac{2-4}{2}=-1$

Saludos!