Question

Resuelve las siguientes ecuaciones:

4(x-1)+2(x+2)=3(x+4)









x/2+3x/4=x/8+9







(3x+2)/4-(x+1)/3=(2x-1)/6-(1-x)/2

Answer 1

$4(x-1)+2(x+2)=3(x+4) \\ 4x - 4 + 2x + 4 = 3x + 12 \\ 6x = 3x + 12 \\ 6x - 3x = 12 \\ 3x = 12 \\ x = \frac{12}{3} \\ x = 4$

$\frac{x}{2} + \frac{3x}{4} = \frac{x}{8} + 9 \\ 8( \frac{x}{2} + \frac{3x}{4} ) = 8( \frac{x}{8} + 9 ) \\ 4x + 6x = x + 72 \\ 10x = x + 72 \\ 10x - x = 72 \\ 9x = 72 \\ x = \frac{72}{9} \\ x = 8$

$\frac{3x + 2}{4} - \frac{x + 1}{3} = \frac{2x - 1}{6} - \frac{1 - x}{2} \\ 12( \frac{3x + 2}{4} - \frac{x + 1}{3} ) = 12( \frac{2x - 1}{6} - \frac{1 - x}{2} ) \\ 3(3x + 2) - 4(x + 1) = 2(2x - 1) - 6(1 - x) \\ 9x + 6 - 4x - 4 = 4x - 2 - 6 + 6x \\ 5x + 2 = 10x - 8 \\ 2 + 8 = 10x - 5x \\ 10 = 5x \\ \frac{10}{5} = x \\ 2 = x$