Question

resuelve las siguientes ecuaciones


4(e+3)-11(e-7)=4(e-7)=4(5e+2)

4(x+3)=6(x-1)

7(m+3)=45-3(12-m)

4(n-1)+5(n+1)=100​

Answer 1

Respuesta:

4(e + 3) -11 (e - 7) = 4 (e - 7) = 4 (5e + 2)

4e + 12 - 11e + 77 = 20e + 8

-7e + 89 = 20e + 8

-7e - 20e = 8 - 89

-27e = -81

e = 3

4(x + 3) = 6 (x - 1)

4x + 12 = 6x - 6

-2x = -18

x = 9

7(m + 3) = 45 - 3 (12 - m)

7m + 21 = 45 - 36 + 3m

7m + 21 = 9 + 3m

7m - 3m = 9 - 21

4m = - 12

m = -3

4(n - 1) + 5 (n + 1) = 100

4n - 4 + 5n + 5 = 100

9n + 1 = 100

9n = 100 - 1

9n = 99

n = 11

Explicación paso a paso:

Saludos ^^