Question

resuelve las siguientes ecuaciones

1°
2/3 (2/5y+3/6)=2/3 (2/4y - 3/5)


2° x/3 - 2= x/9

Answer 1

Bueno :
1) 2/3 (2y/5 +3/6) =2/3 (2y/4-3/5)
=> 2y/5 + 3/6 =2y/4 - 3/5
=> 4y + 5 = 5y -6
=> y=11

2) x/3 -2 = x/9
=> (x-6)/3 = x/9
=> x-6 = x/3
=> 3(x-6) =x
=> 3x-18=x
=> 2x=18
=> x=9

Espero te sirva!!!

Answer 2

¡Hola!

I.
$\frac{2}{3} ( \frac{2}{5} y + \frac{3}{6} ) = \frac{2}{3} ( \frac{2}{4} y - \frac{3}{5} ) \\ \frac{2}{5} y + \frac{3}{6} = \frac{2}{3} \div \frac{2}{3} ( \frac{2}{4} y - \frac{3}{5} ) \\ \frac{2}{5} y + \frac{1}{2} = \frac{1}{2} y - \frac{3}{5} \\ \frac{1}{2} + \frac{3}{5} = \frac{1}{2} y - \frac{2}{5} y \\ \frac{11}{10} = \frac{1}{10} y \\ \frac{11 \times 10}{10} = y \\ 11 = y$

II.
$\frac{x}{3} - 2 = \frac{x}{9} \\ \frac{x}{3} - \frac{x}{9} = 2 \\ \frac{6}{27} x = 2 \\ \frac{2}{9} x = 2 \\ x = 9$

Espero que te sirva de ayuda ^^

Saludos: Margareth ✨