Resuelve las ecuaciones:
2·x = x+3
9·x-6 = 2·x+1
5·(x-1)-6·x = 3·x-9
6·(x+11) = 40+6·(x+2)
7·(x+3) = 3·(x+7)
8·(x-1) = 2·(3·x+5)-22
ACLARO QUE x ES equiz. No es el signo de por
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Despejando la variable " x " :
1 )
2x = x + 3
2x - x = 3
x = 3
2 )
9x - 6 = 2x + 1
9x - 2x = 1 + 6
7x = 7
x = 7/7
x = 1
3 )
5 ( x - 1 ) - 6x = 3x - 9
5x - 5 - 6x = 3x - 9
5x - 6x - 3x = - 9 + 5
- 4x = - 4
x = -4/ -4
x = 1
4 )
6 ( x + 11 ) = 40 + 6 ( x + 2)
6x + 66 = 40 + 6x + 12
6x - 6x = 40 + 12 - 66
0 = 0
C.S { ∅ } → Conjunto de solucion el conjunto vacio " ∅ "
5 )
7 ( x + 3) = 3 ( x + 7 )
7x + 21 = 3x + 21
7x - 3x = 21 - 21
5x = 0
x = 0
6 )
8 ( x - 1 ) = 2 ( 3x + 5 ) - 22
8x - 8 = 6x + 10 - 22
8x - 6x = 10 - 22 + 8
2x = - 4
x = - 4 / 2
x = - 2
1 )
2x = x + 3
2x - x = 3
x = 3
2 )
9x - 6 = 2x + 1
9x - 2x = 1 + 6
7x = 7
x = 7/7
x = 1
3 )
5 ( x - 1 ) - 6x = 3x - 9
5x - 5 - 6x = 3x - 9
5x - 6x - 3x = - 9 + 5
- 4x = - 4
x = -4/ -4
x = 1
4 )
6 ( x + 11 ) = 40 + 6 ( x + 2)
6x + 66 = 40 + 6x + 12
6x - 6x = 40 + 12 - 66
0 = 0
C.S { ∅ } → Conjunto de solucion el conjunto vacio " ∅ "
5 )
7 ( x + 3) = 3 ( x + 7 )
7x + 21 = 3x + 21
7x - 3x = 21 - 21
5x = 0
x = 0
6 )
8 ( x - 1 ) = 2 ( 3x + 5 ) - 22
8x - 8 = 6x + 10 - 22
8x - 6x = 10 - 22 + 8
2x = - 4
x = - 4 / 2
x = - 2
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