Question

resuelve la siguiente ecuacion logaritmica
log 4 + 2log(x-3)=logx

Answer 1

Respuesta:

$log4 + 2log(x - 3) = logx \\ log4 + log {(x - 3)}^{2} = logx \\ log(4( { x - 3)}^{2} ) = logx \\ 4( {x}^{2} - 6x + 9) = x \\ 4{x}^{2} - 24x + 36 = x \\ 4 {x}^{2} - 25x + 36 = 0 \\ x1 = 9/4 \\ x2 =4$