Question

Resuelve la ecuación cuadrática utilizando la fórmula general
X²-3x+2=0

Answer 1

Respuesta:

La formula general es

$x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}$

Donde sabemos:

a = 1

b = -3

c = 2

Remplazamos:

$x_{1} =\frac{-(-3)+\sqrt{(-3)^{2}-4(1)(2) } }{2(1)}\\ \\x_{1} = \frac{3 + \sqrt{9 -8} }{2} \\ \\x_{1} = \frac{3+\sqrt{1} }{2}\\ \\ x_{1} = \frac{3+1}{2}\\ \\ x_{1} = \frac{4}{2}\\ \\x_{1} = 2\\\\\\x_{2} = \frac{-(-3)-\sqrt{(-3)^{2}-4(1)(2) } }{2(1)}\\ \\x_{2} = \frac{3 - \sqrt{9 -8} }{2} \\ \\x_{2} = \frac{3-\sqrt{1} }{2}\\ \\ x_{2} = \frac{3-1}{2}\\ \\ x_{2} = \frac{2}{2}\\ \\x_{2} = 1$

C.S {2, 1}