Question

resuelve la ecuación:

Answer 1

Respuesta:

$\frac{x^{2}+4 }{(x-3)(x-5)} = \frac{4}{15}\\\\\frac{x^{2} +4}{x^{2} -5x-3x+15} =\frac{4}{15}\\\\\frac{4}{-5x-3x+15x} =\frac{4}{15}\\\\15(4) = 4(-5x-3x+15x)\\15 = -5x-3+15x\\15+3=-5x+15x\\18=10x\\x=1.8$