Question

resuelve el sistema (1). 3x+5y=1 (2).4x+2y=-6​

Answer 1

Explicación paso a paso:

$3x + 5y = 1 \\ 3x = 1 - 5y \\ x = \frac{1 - 5y}{3} \\ 4x + 2y = - 6 \\ 4 \times \frac{1 - 5y}{3} + 2y = - 6 \\ \frac{4 - 20y}{3} + 2y = - 6 \\ \frac{4 - 20y}{3} + \frac{6y}{3} = - 6 \\ \frac{4 - 20y + 6y}{3} = - 6 \\ 4 - 14y = - 18$

$- 14y = - 18 - 4 \\ - 14y = - 22 \\ 14y = 22 \\ y = \frac{22}{14} = \frac{11}{7}$

$x = \frac{ 1- 5y}{3} = \frac{1 - 5 \times \frac{11}{7} }{3} = \\ \frac{1 - \frac{55}{7} }{3} = \frac{ \frac{7}{7} - \frac{55}{7} }{3} = \\ \frac{ \frac{ - 48}{7} }{3} = \frac{ - 48}{7} \times \frac{1}{3} = \frac{ - 48}{21} = \frac{ - 16}{7}$

$3 \times \frac{ - 16}{7} + 5 \frac{11}{7} = \frac{ - 48}{7} + \frac{55}{7} = \frac{7}{7} = 1$

$4 \frac{ - 16}{7} + 2 \frac{11}{7} = \frac{ - 64}{7} + \frac{22}{7} = \frac{ - 42}{7} = - 6$

espero te sirva