Question

resuelve 2/3m²-2mn+1/10m²-1/3mn+2mn-2m²​

Answer 1

Respuesta:

$\frac{2}{3}m^2-2mn+\frac{1}{10}m^2-\frac{1}{3}mn+2mn-2m^2\\\\\\\frac{2}{3}m^2+\frac{1}{10}m^2-2m^2-2mn-\frac{1}{3}mn+2mn\\\\\\-\frac{37}{30}m^2-2mn-\frac{1}{3}mn+2mn\\\\\\-\frac{37}{30}m^2-\frac{1}{3}mn\\\\\\-\frac{37m^2}{30}-\frac{mn}{3}$