Question

Resuelva los ejercicios dados a continuacion, aplicando las leyes de las potencias.
porfa ayuda ​

Answer 1

${4}^{3} \times {4}^{ - 2} \times {4}^{2} = {4}^{3 - 2 + 2} = {4}^{3} = 64$

$( {5}^{3} {)}^{2} = {5}^{3 \times 2} = {5}^{6}$

${6}^{ - 2} = \frac{1}{ {6}^{2} } = \frac{1}{36}$

${49}^{ \frac{1}{2} } = \sqrt{49} = 7$

$( \frac{5}{3} {)}^{ - 3} = ( \frac{3}{5} {)}^{3} = \frac{27}{125}$

$\frac{ {5}^{4} }{ {5}^{2} } = {5}^{4 - 2} = {5}^{2} = 25$

$\frac{ {m}^{3} }{ {m}^{7} } = {m}^{3 - 7} = {m}^{ - 4} = \frac{1}{ {m}^{4} }$