Question

respuesta y procedimiento de las siguientes ecuaciones lineales.
5x-12=3
3x+1=x-3
5t+5=3t+7
6x-10=20
5c+3=12-2c
X -10+15=25
5m+150=120​

Answer 1

Respuesta:

5x - 12 = 3

5x = 15

x = 3

3x + 1 = x - 3

3x - x = - 3 - 1

2x = -4

x = - 4/2

x = -2

5t + 5 = 3t + 7

5t - 3t = 7 - 5

2t = 2

t = 2/2

t = 1

6x - 10 = 20

6x = 20 + 10

6x = 30

x = 30/6

x = 5

5c + 3 = 12 - 2c

5c + 2c = 12 - 3

7c = 9

c = 9/7

x - 10 + 15 = 25

x + 5 = 25

x = 25 - 5

x = 20

5m + 150 = 120

5m = 120 - 150

5m = - 30

m = -6

Answer 2

Respuesta:

5x - 12 = 3

5x = 15

x = 3

3x + 1 = x - 3

3x - x = - 3 - 1

2x = -4

x = - 4/2

x = -2

5t + 5 = 3t + 7

5t - 3t = 7 - 5

2t = 2

t = 2/2

t = 1

6x - 10 = 20

6x = 20 + 10

6x = 30

x = 30/6

x = 5

5c + 3 = 12 - 2c

5c + 2c = 12 - 3

7c = 9

c = 9/7

x - 10 + 15 = 25

x + 5 = 25

x = 25 - 5

x = 20

5m + 150 = 120

5m = 120 - 150

5m = - 30

m = -6