Question

resolver sistema de ecuaciones
чy + х=10
2x + y=0​

Answer 1

Explicación paso a paso:

$2x + y = 0 \\ 2x = 0 - y \\ 2x = - y \\ x = \frac{ - y}{2}$

$4y + x = 10 \\ 4y + \frac{ - y}{2} = 10 \\ \frac{8y}{2} + \frac{ - y}{2} = 10 \\ \frac{8y - y}{2} = 10 \\ \frac{8y - y}{2} = \frac{20}{2} \\ 8y - y = 20 \\ 7y = 20 \\ y = \frac{20}{7}$

$4y + x = 10 \\ 4 \times \frac{20}{7} + x = 10 \\ \frac{80}{7} + x = 10 \\ \frac{80}{7} + \frac{7x}{7} = \frac{70}{7 } \\ 80 + 7x = 70 \\ 7y = 70 - 80 \\ 7y = - 10 \\ y = \frac{ - 10}{7}$

comprobamos=

$4 \times \frac{20}{7} + \frac{ - 10}{7} = \frac{80}{7} + \frac{ - 10}{7} = \\ \frac{ 70}{7} = 10$

$2 \times \frac{ - 10}{7} + \frac{20}{7} = \frac{ - 20}{7} + \frac{20}{7} = 0$

espero te sirva