Question

resolver por la regla de Cramer 3a-2b=13 y 2a+4b=3

Answer 1

regla de cramer
3a-2b=13 
2a+4b=3    

Δs= 16
Δa = 58
Δb = -17

Δs= $\left[\begin{array}{ccc}3&-2\\2&4\end{array}\right]$ = 12 - (- 4) = 16 

Δa= $\left[\begin{array}{ccc}13&-2\\3&4\end{array}\right] = 52 -(-6) =58$

Δb = $\left[\begin{array}{ccc}3&13\\2&3\end{array}\right] = 9 - 26 = -17$


 a =  $\frac{Δa}{Δs} = 58/16 = 29/8$
 b =  $\frac{Δb}{Δs}= -17/16$