Question

resolver los siguientes logaritmica
5 (×+3)=11
4 (×-1)=64
8(×+4)=32 (×-2)

Answer 1

1)
log 11 base 5 = x +3
x = log 11 base 5 -3
x = -1.51

2)log 64 base 4 = x-1
(1/2)log 64 base 2 = x-1
(6/2) log 2 base 2 = x-1
3 = x-1
x = 4

3)
2^(3(x+4)) = 2^(5(x-2))
3(x+4) = 5(x-2)
3x + 12 = 5x -10
22 = 2x
x = 11

4)
4e^(3x) = 30
e^(3x) = 7.5
lne^(3x) = ln7.5
3x = ln(7.5)
x = (ln(7.5))/3
x = 0.67 (aprox)